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Write a method called wordLengths that accepts a Scanner representing an input file as its argument. Your method should read from the given file, count the number of letters in each token in the file, and output a result diagram of how many words contain each number of letters. Use tabs before the asterisks so that they'll line up. If there are no words of a given length, omit that line from the output.

For example, if the file contains the following text:

Before sorting:
13 23 480 -18 75
hello how are you feeling today

After sorting:
-18 13 23 75 480
are feeling hello how today you

your method should produce the following output to the console:

2: 6    ******
3: 10   **********
5: 5    *****
6: 1    *
7: 2    **
8: 2    **

You may assume that no token in the file is more than 80 characters in length.

My Code:

public class WordLengths {

WordLengths() {}
  
public static void wordLengths(Scanner scan) {
int[] lengthCountArray = new int[100];
for(int i = 0; i < 100; ++i) {
lengthCountArray[i] = 0;
}
while(scan.hasNextLine()) {
String line = scan.nextLine();
String[] words = line.split("\\s+");
for(int i = 0; i < words.length; ++i) {
int length = words[i].length();
++lengthCountArray[length];
}
}
for(int i = 1; i <= 80; ++i) {
if(lengthCountArray[i] > 0) {
System.out.print(i + ": " + lengthCountArray[i] + "\t");
for(int j = 1; j <= lengthCountArray[i]; ++j) {
System.out.print("*");
}
System.out.println("");
}
}
}
  
public static (String[] args) throws FileNotFoundException {
// say input filename is "input.txt";
String filename = "input.txt";
Scanner scan = new Scanner(new File(filename));
//WordLengths.wordLengths(scan);
}
}

Errors:

Your code did not compile. Please read and correct the errors below.

  • Line 29

    You have an illegal description of a data type here. Sometimes this happens when you misuse the syntax for generic types.

    illegal start of type

    public static (String[] args) throws FileNotFoundException { ^

  • Line 29

    You may have forgotten to end a statement with a semicolon. Each Java statement must end with a semicolon.

    ';' expected

    public static (String[] args) throws FileNotFoundException { ^

  • Line 29

    You have an illegal description of a data type here. Sometimes this happens when you misuse the syntax for generic types.

    illegal start of type

    public static (String[] args) throws FileNotFoundException { ^

  • Line 29

    You may have forgotten to type an identifier here, such as a variable's name or type.

    expected

    public static (String[] args) throws FileNotFoundException { ^

  • Line 29

    You may have forgotten to end a statement with a semicolon. Each Java statement must end with a semicolon.

    ';' expected

    public static (String[] args) throws FileNotFoundException { ^

  • Line 29

    You have an illegal description of a data type here. Sometimes this happens when you misuse the syntax for generic types.

    illegal start of type

    public static (String[] args) throws FileNotFoundException { ^

  • Line 29

    You may have forgotten to type an identifier here, such as a variable's name or type.

    expected

    public static (String[] args) throws FileNotFoundException { ^

  • Line 29

    You may have forgotten to end a statement with a semicolon. Each Java statement must end with a semicolon.

    ';' expected

    public static (String[] args) throws FileNotFoundException { ^ 8 errors

Java, Programming

  • Category:- Java
  • Reference No.:- M9451293

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