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Employ operator () instead of operator[].

While you have multiple subscripts, the cleanest way to do it is along with operator () instead of with operator[]. The reason is that operator[] always takes specifically one parameter, however operator() can take any number of parameters (in the case of rectangular matrix, two parameters are required).

For instance:

class Matrix {

public:

Matrix(unsigned rows, unsigned cols);

double& operator() (unsigned row, unsigned col);  subscript operators frequently come in pairs double operator() (unsigned row, unsigned col) const;  subscript operators frequently come in pairs

...

~Matrix(); // Destructor

Matrix(const Matrix& m); // Copy constructor

Matrix& operator= (const Matrix& m); // Assignment operator

... private:

unsigned rows_, cols_;

double* data_;

};

inline

Matrix::Matrix(unsigned rows, unsigned cols)

: rows_ (rows)

, cols_ (cols)

//data_ <--initialized below (after the 'if/throw' statement)

{

if (rows == 0 || cols == 0)

throw BadIndex("Matrix constructor contain 0 size");

data_ = new double[rows * cols];

}

inline

Matrix::~Matrix()

{

delete[] data_;

}

inline

double& Matrix::operator() (unsigned row, unsigned col)

{

if (row >= rows_ || col >= cols_)

throw BadIndex("Matrix subscript is beyond bounds");

return data_[cols_*row + col];

}

inline

double Matrix::operator() (unsigned row, unsigned col) const

{

if (row >= rows_ || col >= cols_)

throw BadIndex("const Matrix subscript is beyond bounds");

return data_[cols_*row + col];

}

You can then access an element of Matrix m via m(i,j) instead of m[i][j]:

int main()

{

Matrix m(10,10); m(5,8) = 106.15; std::cout << m(5,8);

...

}

C/C++, Programming

  • Category:- C/C++
  • Reference No.:- M9529214

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