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Convert the following C program to MIPS program. Assuming that i, j, k, f, are stored in registers $s0, $s1, $s2, $s3 already.

 

A.) f = i + j - k;

 

B.) f = i + ( j - 8 );

 

C.) f = -i + ( j + 3); (Hint: $zero)

 

D.) f = i * 4; (Hint: Relationship between multiplication and shift)

 

E.) f = i/2 + 2;

 

F.) f = i;

 

G.) f = -i;

 

H.) i++;

 

 

C/C++, Programming

  • Category:- C/C++
  • Reference No.:- M9457206

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