An elementary calculation yields the result that theoretically, the probability of turning up 7 when two dice are thrown is 1/6, or .166666. But what if more dice are thrown? If 3 dice are thrown, what is the probability that some 2 of three sum to 7? (Thus if 2-2-1 or 2-2-3 are thrown, no pair of dice sum to 7, so these combinations are failures, but if 2-3-4 or 2-3-5 or 1-2-5 are thrown, in each case a sum of 7 IS achievable with exactly 2 of the dice).

For this problem, you are to start with the driver below, which first prompts for the number of dice tossed - here, diceCount, and then runs a million experiments to determine the empirical likelihood that with that many dice rolled, some pair of the dice thrown sum to 7:

import java.util.Scanner;   
public class SevenDriver{       
  public static void main(String[] args){      
    System.out.println("Enter number of dice to toss");     
    Scanner s = new Scanner(System.in);      
    int diceCount = s.nextInt(); 
    SevenTally t = new SevenTally(diceCount);
    int experiments = 1000000;
    int wins = 0;
    for(int j = 0; j < experiments; j++)
      if(t.experiment()) wins++;
    System.out.println((double)wins/experiments);
        
  } 
}