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Two genes are located on the same chromosome and are known to be 12 mu apart. An AABB individual was crossed to an aabb individual to produce AaBb offspring. The AaBb offspring were then crossed to aabb individuals.
A. If this cross produces 1,000 offspring, what are the predicted numbers of offspring with each of the four genotypes: AaBb, Aabb, aaBb, and aabb?
B. What would be the predicted numbers of offspring with these four genotypes if the parental generation had been AAbb and aaBB instead of AABB and aabb?
Answer:
A. Because they are 12 mu apart, we expect 12% (or 120) recombinant offspring. This would be approximately 60 Aabb and 60 aaBb plus 440 AaBb and 440 aabb.
B. We would expect 60 AaBb, 60 aabb, 440 Aabb, and 440 aaBb.

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