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Two gene loci, A and B, assort independently, and alleles A and B are dominant over alleles a and b. Indicate the probability of producing: An aB phenotype from a cross AaBb x AaBB. My answer would be: 1/2 x 4/4= 2/4 x 4/4 = 8/16= 1/2 I'm having trouble with these types of problems. I set them up using the punnett square. Is there an easier way?

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