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In a cylindrical nuclear fuel rod, heat is generated internally according to q'''(r)=q0'''[1-(r/r0)^2], where q0''' is the volumertic heat generation rate at the centerline, r=0. Calculate the temperature drop from the centerline to the surface for a 1-inch OD rod having a thermal conductivity of 15 BTU/hrft F (26 W/mK), if the rate of heat removal from the rod surface is 500,000 BTU/hrft^2 (1.5775 MW/m^2).

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