(Answered) If you cross a male fruit fly that has a black body amp is

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If you cross a male fruit fly that has a black body & is eyeless (both mutations) to female that is homozygous Wild Type at both loci, the F1 progeny are all Wild Type. If you then cross an F1 male with an F1 female you obtain the following results: black body 192, Wild type 662, black body & eyeless 81, & eyeless 229. Propose an explanation for this result i.e., what is the pattern of inheritance for each gene (remember to show your work)?

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