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Two intracellular molecules X and Y are both usually synthesized at a constant rate of 1000 molecules per second per cell. Molecules X is broken down slowly: each and every molecule of X survives on average for 100 seconds; Molecule Y is broken down 10 times faster, each molecule of Y services on average for 10 seconds.

a) Compute how many molecules X and Y the cell includes at any time.

b) If the rates of synthesis of both X and Y are suddenly raised tenfold to 10,000 molecules per second per cell devoid of any change in their degradation rates-how many molecules of X and Y will there be after one second?

c) Which molecule would be preferred for the rapid signaling? describe why?

d) Which molecule would be favored for slow signaling? describe why?

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  • Category:- Biology
  • Reference No.:- M937131

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