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If I had 1L of a 1.0M solution of glycine at the isoelectric pH (6.02) and I added 0.3 mol of HCL, what would be the new pH? Describe what would be the pH if I added 0.3 mol of NaOH rather than the acid?

I know that the Henderson-Hasselbalch equation must be used (pH = pk + log [conj base/conj.acid]), however I can only see this giving me the pK if I were to employ this equation. Is glycine the buffer in this problem? Please help me learn precisely how to properly do this problem.

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