Consider the reaction: PCl5 (g) = PCl3 (g) + Cl2 (g)
for which Kp= 1.05 @ 250C. A quantity of 2.50g of PCl5 is placed in an evacuated flask of volume 0.500 L and heated to 250C.
(a) Calc the pressure of PCl5 if it did not dissociate.
(b) Calc the partial pressure of PCl5 at equilibrium.
(c) What is the total pressure at equilibrium?
(d) What is the degree of dissociation of PCl5? (The degree of dissociation is given by the fraction of PCl5 that has undergone dissociation.)