One-thousand individuals were screened for their genotype at the MN blood group locus. The numbers of each genotype were:
MM MN NN
298 489 213
Assuming random mating, find out the gene frequency for the M allele and the expected genotype frequencies. Use the chi-squared test to determine that mating is random.
MM MN NN
298 213
298/1000 0.289 489/1000 0.489 213/100 0.213
Assuming random mating, find out the gene frequency for the M allele and the expected genotype frequencies. Use the chi-squared test to determine that mating is random.
Using gene count method
Frequency of M ALLELE= D+H/2==0.289 +0.489/2=0.289 +0.2445=0.5335= ROUNDED 0.54
Frequency of NALLELE= D+H/2==0.213+0.489/2=0.213 +0.2445=0.4575= ROUNDED 0.46
Genotype OBSERVED EXPECTED O-E (O-E)^2/E
MM P^2 289 0.54 X0.54 X1000= 291.6=292 3 0.03
MN 2PQ 489 2X0.54X0.46X1000 496.8=497 64 0.12
NN Q^2 213 0.46X0.46X1000 211.6=211 4 0.01
1000 1000 0.16
find outD VALUE IS LESS THAN THE TABLE VALUE AT 5% LEVEL OF SIGNIFACE , HENCE THE NULL HYPOTHEISS IS ACEPTED , IT IS IN HARDY WEINBERG QUILIBRIUM

problem:

2. Compare and contrast h2 and H2. Discuss the limitations of each in determining heritability, especially in humans.