(Answered) An enzyme has a kmnbspof 20 microm and a vmaxnbspof 50

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An enzyme has a K_M of 20 µM and a V_max of 50 mmoles of product/minute/µg of enzyme.

After exposure to an inhibitor and analysis on a Lineweaver - Burk plot the following values are obtained: -1/ K_M = - 0.05 liters/µmole and 1/ V_max = 0.04 (mmoles of product/minute/µg of enzyme).

What kind of inhibitor was used in the experiment?

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