An enzyme has a km of 20 microm and a vmax of 50, Ask an Expert

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An enzyme has a KM of 20 µM and a Vmax of 50 mmoles/minute/µg. After exposure to an inhibitor and analysis on a Lineweaver - Burk plot the following values are obtained: -1/KM = - 0.05 liters/µmole and 1/Vmax = 0.04 (mmoles of product/minute/µg of enzyme)-1. What kind of inhibitor was used in the experiment?

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