Question: A female rabbit with hemophilia, rickets and a tail was mated to a male rabbit that did not have hemophilia or rickets but lacked a tail. The F1 females were all wild type, that is, not having hemophilia or rickets but having a tail. The F1 males had hemophilia, rickets and tails. A cross of F1 females to F1 males produced the following offspring in the F2 generation:
|
Hemophilia
|
Rickets
|
Tails
|
Males
|
Females
|
|
Hemophilia
|
No rickets
|
Tail-less
|
2
|
0
|
|
No hemophilia
|
Rickets
|
Tail
|
3
|
48
|
|
Hemophilia
|
Rickets
|
Tail-less
|
63
|
0
|
|
No hemophilia
|
No rickets
|
Tail
|
57
|
194
|
|
Hemophilia
|
No rickets
|
Tail
|
40
|
52
|
|
No hemophilia
|
Rickets
|
Tail-less
|
35
|
0
|
|
Hemophilia
|
Rickets
|
Tail
|
146
|
206
|
|
No hemophilia
|
No rickets
|
Tail-less
|
154
|
0
|
- What are the genotypes of the original parents in this cross? Write each genotype to show which alleles are linked together on the same chromosome.
- What are the genotypes of the F1 males and females? Write each genotype to show which alleles are linked together on the same chromosome.
- Draw a genetic map showing the distances between these genes. Express the distances in map units.
- What is the degree of interference?