A current of it 100 cos 10 kt - 45deg ma is applied across, Ask an Expert

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A current of i(t) = 100 cos (10 kt - 45°) mA is applied across a parallel connection of a 1.5-kΩ resistor, a 150-mH inductor, and a 0:0667-μF capacitor. Use current division to find the steady-state currents i_C(t) , i_L(t), and i_R(t) through each of the three elements.

Find the phasor voltage across the parallel connection. Draw a phasor diagram showing V, I_C, I_L, and I_R. Comment on the results.

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Electrical & Electronics, Engineering

Category:- Electrical & Electronics
Reference No.:- M92050138

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