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In order to make 50.0 mL of a 0.050 M AlCL3 aqueous solutio, how many grams of solid AlCl3 must be used? (o.050 M AlCl3 means 0.050 moles AlCl per exactly 1 liter of solution)

Write a dissociation equation of AlCl3 showing its sepatation into aqueous ions.

What is the total concentation (molarity, M) of all ions together in a 0.050 M AlCl3 solution?

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Category:- Chemistry
Reference No.:- M9456234

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