Which is the equivalence-point pH if 25.0 mL HCOOH (1.8 x 10-4) requires 29.80 mL 0.3567 M NaOH to reach the equivalence point?
Answer
A. 2.06
B. 5.48
C. 8.52
D. 9.26
Which process best accounts for the numerical value of the equivalence-point pH after the titration of formic acid, HCOOH with NaOH?
Answer
A. HCOO- (aq) + H2O (l) <--------> HCOOH (aq) + OH- (aq)
B. HCOOH(aq) + H2O(l) <-------> -COOH (aq) + H3O+ (aq)
C. HCOOH (aq) + H3O+ (aq) <--------> HCOOH2+ (aq) + H2O(l)
D. HCOOH(aq) + H2O(l) <-------> HCOOH2+ (aq) + OH- (aq)