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When the parachute opens in a sky jump, the forces acting on a sky diver of mass m kg, are his weight of magnitude mg and a resistive force of magnitude kv2, where v ms-1 is his speed and k is a positive constant.

Calculate his terminal speed vT, in ms-1, when m = 70.6 kg and k = 38.29, giving your answer to 3 decimal places. Assume g = 9.81 ms-2.
Please provide working and answer for better understanding.

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