When the ore lead (ll) sulfide burns in oxygen, the products are lead (ll) oxide and sulfur dioxide.
Part A: Balance the equation:
express the answer as a chemical equation. identify all of the phases in your answer
PbS(s) + O2(g) --> PbO(s) + SO2(g)
Part B: How many grams of oxygen are required to react with 0.128 mole lead (ll) sulfide?
Part C: How many grams of sulfur dioxide can be produced when 66.0g lead(ll) sulfide react?
Part D: How many grams of lead(ll) sulfide are used to produce 129g lead(ll) oxide?