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When PCl3(g) (420.9 grams) and 0.007859 mol/L of Cl2(g) in a 390.0 L reaction vessel at 340.0 °C are allowed to come to equilibrium the mixture contains 200.7 grams of PCl5(g). What concentration (mol/L) of PCl3(g) reacted? PCl3(g)+Cl2(g) = PCl5(g)

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