When a basic solution of croh4- ion is slowly acidified, Ask an Expert

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When a basic solution of Cr(OH)4- ion is slowly acidified, solid Cr(OH)3 precipitates out and then redissolves in excess acid. If Cr(OH)4- exists as Cr(H2O)2(OH)4-, write equations that represent these two reactions. (Use the lowest possible coefficients. Include states-of-matter under SATP conditions in your answer.)

1) Precipitation Equation = ?
2) Redissolving Equation = ?

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