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1. What was the calculated PH value obtained for the reaction NH3 + HCl -› NH4Cl using the thermodynamic data NaOH (aq) + HCl (aq)--> H2O(l) +NaCl (aq) NaOH (aq) + NH4Cl(aq)---> NH3 + NaCl + H2O(l) NH4Cl 2M 20ml NH4OH 2M 10ml HCL 2M 20ml NaOH 2M 20ml a.-52.2 kJ b.80.29kJ c.-167.2kJ d.-80.29kJ e.52.2kJ Please show work as I am completely lost

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