1) 0.121 grams of oxalic acid dihydrate (MW=126.068 g/mole) is dissolved in water in an Erlenmeyer flask. Remember that each mole of oxalic acid dissolved in water results in 2 moles of hydronium ion so it takes 2 moles of NaOH to neutralize one mole of oxalic acid. It requires 14.22 mLs of your prepared sodium hydroxide solution to reach the endpoint of the titration. What is the molarity of your NaOH solution? 2) You are given an impure sample of oxalic acid dihydrate (MW=126.068 g/mole) and asked to determine the percent of oxalic acid dihydrate present in the sample. You place 0.110 grams of the unknown sample in an Erlenmeyer flask and dissolve it in distilled water. Titration with 0.140 M standardized NaOH solution requires 10.10 mLs to reach the titration endpoint. What is the percent of oxalic acid dihydrate in the sample? 3)A 20.00 mL of a sample of vinegar of unknown concentration was titrated with 21.63 mL of 0.102 M sodium hydroxide solution. How many moles of acetic acid are present in the 20.00 mL sample? 4) A 20.00 mL of a sample of vinegar of unknown concentration was titrated with 18.91 mL of 0.132 M sodium hydroxide solution. How many moles of acetic acid are present in the 20.00 mL sample?