A procedure for determining the amount of iron in a sample is to convert the iron to Fe2+ and then titrate with the solution of Ce(NH4)2(NO3)6
Fe2+(aq) + Ce 4+(aq) --> Fe3+(aq) + Ce3+(aq)
What is the mass percentage of iron in a sample if titration of 1.2284g of the sample requires 57.91 mL of .1018M of Ce(NH4)2(NO3)6 for complete reaction?