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What is the concentration of 50 mL of a solution of NaOH if 25 mL of HCl 0.1M are needed to reach the equivalence point during a titration?
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A student is doing the experiment Chemical Formulas of Copper Sulfide by heating copper with excess of sulfur at very high temperatures using a Bunsen burner. Copper and sulfur react stoichiometrically and excess of sulf ...
A mixture containing 3.3 moles of NO and 0.76 mole ofCO 2 was allowed to react in a flask at a certaintemperature according to the equation. NO (g) + CO 2 (g) ↔ NO2 (g) + CO (g) At equilibrium 0.21 mole of CO 2 was pr ...
Why do the instructions call for using a saturated solution of NaOH rather than one at lower concentration? Why can we ignored in the calculation of the concentration of NaOH?
How many formula units of Na2SO4are present in a 450 gram sample of the salt? Use 6.022×1023mol-1 or Avogadro's number. Report your answer in scientific notation. Your answer should have two significant figures.
What would an increase in the metal wire mass indicate when the metal wire starts to form copper on it from a chemical reaction from 6M HCl and copper (II) sulfate pentahydrate? What would a decrease in the metal wire ma ...
What is the volume of a solution with a concentration of 1.2 M that contains 12 g of NaOH?
Match the reaction provided on the left with the correct reaction classification/type on the right [NOTE the reaction equations are not balanced] . Reaction classification/types can be used more than once or not at al ...
Explain why the mass of the crucible and anhydrous salt is less than the mass of the crucible and the hydrate. What is the chemical formula of copper (II) sulfate?
Determine if the reactants shown on the right would result in the formation of a precipitate. Choices can be used more than one time or not at all. Forms a precipitate Will not form a precipitate Na 2 SO 4 + Ba(NO 3 ) 2 ...
While heating your copper sulfur mixture the original crucible lid fell and was broken. You replace the lid with another one. You used the mass of the original lid in your calculations. However the mass of the second lid ...
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