If the volume (in cm^3) of an ethanol/water mixture at 298K in 1kg of water can be expressed in polynomial form, vs the number of moles of ethanol (nEtOH), as 1002.93+54.6664*nEthOH-0.36394*nEthOH^2+0.028256*nEtOH^3, the partial molar volume of ethanol has its minimum value at m > 0.004 mol/kg.