|
VI (ml)
|
150.0
|
|
VF (ml)
|
165.5
|
|
TI (?C)
|
68.0
|
|
TF (?C)
|
57.0
|
|
|
|
?V (ml)
|
15.5
|
|
?T (?C)
|
-11.0
|
1. Calculate the heat lost by the hot water. (See the equation in the Introduction.) Express your answer in calories and Joules. Show your work.
- Heat(cal)=(mass(g))(Cp)(?T)
- Heat=(150g)( 1cal/goc)(11oC)
- Heat=1650cal
- 1cal=4.184J
- 1650cal=394J
2. Using the volume of ice melted, convert to mass of ice melted using the density of water of 1 g/mL.
- M=DV
- M=(1g/ml)(15.5ml)
- M=15.5g
3. Convert mass of ice melted to moles of ice melted.
- Moles=g(1mol/molar mass)
- Moles=15.5g(1mol/18.0g)
- =.861mol
4. Calculate the molar heat of fusion of ice in kJ/mol.