Please provide a solution to this problem. There is another answer on there which doesnt fully expain this question and we have been trying to solve it for so long.
To 1.00 L of a 0.100 M aqueous solution of benzoic acid (C6H5COOH) is added 1.00 mL of 12.0 M HCl. What is the percentage ionization of the benzoic acid in the resulting solution? [Ka(C6H5COOH) = 6.5 × 10-5]