(Answered) Ttrate the base trimethylamine tma with 0126 m hcl ch3naq

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Titrate the base trimethylamine (TMA) with 0.126 M HCl. (CH)₃N(aq) + H₂O(l) (CH₃)₃NH+(aq) + OH-(aq)

Kb = 6.45 x 10^-5

There are 0.00615 moles of TMA in 42.5 mL H₂O before titration begins.

What percent of TMA is in the protonated form at the beginning of the titration?

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