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Three masses (A, B and C) with the same momentum are moving across a horizontal frictionless surface. The masses are respectively mA = m, mB = 2m, and mC = m/3. Rank the masses in order of decreasing kinetic energy. That is, the mass with the most kinetic energy is first, and the mass with the least kinetic energy is last. (Use only ">" or "=" symbols. Do not include any parentheses around the letters or symbols. Use A, B, and C to construct your answer.)

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