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2Al (s) +  3H2SO4 (aq) --> Al2(SO4)3 (aq) + 3H2 (g) 

Determine the volume (mL) of 15.0 M sulfuric acid needed to react with 45.0 g of aluminum to produce aluminum sulfate. Determine the % yield if 112 g of aluminum sulfate is produced under the above conditions.

 

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