The velocity of a 47 kg particle is given by vrarr 4ti3t2j, Ask an Expert

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The velocity of a 4.7 kg particle is given by v^→ +(4ti^+3t²J^), where v is in m/s and t is in seconds. At the instant when the net force on the particle has a magnitude of 45 N, what is the angle between the particle's acceleration and the particle's direction of motion? Give your answer in degrees.

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