The quantity of antimony in a sample can be determined by an oxidation reduction titration with an oxidzing agent.
A 7.05 g of stibnite, an ore antimony, is dissolved in hot, concentrated HCL and passed over a reducing agent so that all the antimony is in form Sb^3+ (aq). The Sb^3+ (aq) is completely oxidized by 32.0 mLof a 0.125 M (aq) solution of KBrO3(aq).
The unbalanced equation for the reaction is...
BrO3^-(aq) + Sb^3+ (aq) ---> Br^-(aq) + Sb^5+ (aq)
Calculate the amount of antimony in the sample and it percentage in ore.