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A sample which may contain silver, lead or mercury ions or some combination of these metals, is treated with chloride ions, whereupon a white precipitate is formed. The solution is heated and the hot solution is filtered. When the filtrate is treated with chromate ion (CrO4-2) no precipitate is formed. The remaining white solid in the filter paper has ammonia water poured through it. This turns the precipitate in the filter paper black. The new filtrate is treated with hydrochloric acid (HCl), giving a white precipitate. What metal ion or ions are in the solution? Explain your reasoning.

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