You have learned in class that addicion of an alcohol such as MeOH to this reaction results in a monobromide product instead of a dibromide. Draw the mechanism and all products obtained if you were to react trans-cinnamic acid with Br2 and MeOH. The reaction previously done was just having trans-cinnamic acid reacted with Br2 forming all the isomers with the double bond being broken and Br put into place.