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The reaction: 2 HI → H2 + I2, is second order and the rate constant at 800 K is 9.70 × 10-2 M-1 s-1. How long will it take for 8.00 × 10-2 mol/L of HI to decrease to one-fourth of its initial concentration?

Choose one answer.

a. 0.619 s
b. 387 s
c. 429 s
d. 124 s

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