(Answered) The rate law for the reaction below is given by rate kpph3

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The rate law for the reaction below is given by Rate = k(PPH3). At 680°C, the half-life is 35.0 s. Given initial pressures of PPH3 = 0.67 atm, PP4 = 0.25 atm, and PH2 = 0.75 atm, how many seconds will it take for the pressure of PPH3 to drop to 0.50 atm?

4 PH3(g) → P4(g) + 6 H2(g)

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