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The position of a particle moving with constant acceleration is given by x(t) = 6t2 + 6t + 4 where x is in meters and t is in seconds.

(A) Calculate the average velocity of this particle between t = 6 seconds and t = 10 seconds.

(B) At what time during this interval is the average velocity equal to the instantaneous velocity?

(C) How does this time compare to the average time for this interval? (a) It is larger. (b)It is smaller. (c)They are the same.

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