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The molecular weight and formula of a hydrocarbon are to be determined through the use of the freezing point depression method. The hydrocarbon is known to be 86 percent carbon and 14 percent hydrogen by mass. In the experiment, 3.72 grams of the unknown hydrocarbon were placed into 50.0 grams of liquid benzene, C6H6. The freezing point of the solution was measured to be 0.06 degrees Celsius. The normal freezing point of benzene is 5.50 degrees Celsius, and the freezing point depression constant is 5.12 degrees Celsius/m.

a. What is the molecular weight of the compound?

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