The mercury in a 0.7325 gram unknown sample was, Ask an Expert

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The mercury in a 0.7325 gram unknown sample was precipitated with excess par aperiodic acid, H6IO5, according to the following balanced chemical equation: 5Hg2+(aq) + 2H6IO5(aq) ------> HG5(IO)2(s) + 10H+(aq) The Hg5(IO)2 precipitate was filtered, washed free of precipitating agent, dried, and found to weigh 0.3402 grams. What is the weight percentage of mercury in the sample?

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Category:- Chemistry
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