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The long, straight wire shown in the figure (Figure 1) a carries constant current I = 41.0 A . A metal bar with length L = 49.0 cm is moving at constant velocity v , as shown in part (a) of the figure; the constant speed is 135.0 cm/s . Point a is a distance d = 22.5 cm from the wire.

What is the direction of the v x B vector which will be in your motional EMF integral?

What is the direction of the vector which will be in your motional EMF integral?

Part B. Consider a small length element of the moving bar having a length of 0.199 mm and being located at a distance of 16.333 cm from the end of the rod which is closest to the current. What would be the absolute value of the contribution to the motional EMF integral from this small element of length in the moving bar?

Part C. Consider a small length element of the moving bar having a length of 0.199 mm and being located at a distance of 32.667 cm from the end of the rod which is closest to the current. What would be the absolute value of the contribution to the motional EMF integral from this small element of length in the moving bar?

Part D. Compute the motional EMF integral for this moving bar, and thus determine the absolute value of the induced EMF in the moving bar.

Part E. Now consider the situation in panel (b) of the figure. The bar has been replaced by a rectangular wire loop of length L (the same as the bar) and width W = 47.0 cm (the figure is not drawn to scale); the current in the long straight wire is the same as in panel (a), and the velocity of the loop is the same as the velocity of the bar. Consider doing the motional EMF integral clockwise around the metal loop, starting in the lower left hand corner. What will be the result of this integral for each successive segment of the bar?

Enter your answer as an ordered quadruple. Enter the EMF for the leftmost segment first, followed by a comma, followed by the EMF for the uppermost segment, followed by a comma, followed by the EMF for the rightmost segment, followed by a comma, followed by the EMF for the lowermost segment.

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