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The graph of two cars that collide shows that they intersect at a point 5.5m on a distance/time graph. The first car has a velocity of 0.39m/s. The scond car has a velocity of 0.32m/s. The first line(first car) has a slope of 0.4m/s and the second line (second line) has a slope of -0.3m/s. The actual collision poin is 4.6m while the calculated collision point is 5.5m.

a) How do the two sets of values compare?

b) What does the steepness of the slope indicate?

c) Why is one slope positive and the other negative?

d) What are some reasons for the difference in the actual and calculated collision points?

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  • Category:- Physics
  • Reference No.:- M9891658

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