The formula for the determination of energy is e=hv=hc/lamba where h is planck's constant and c is the speed of light. what is the relationship between wavelength and energy?

(hydrogen) The rydberg equation has the form 1/lamba= Rh(1/nf2 - 1/ni2) where lamba is the wavelength in meters, Rh is the rydberg constant, nf is the final principal quantum (for the balmer series, which is in the visible spectrum, nf=2) and ni is the initial principal quantum number (n=3,4,5,6...). Calculate from data the wavelength in meters and 1/lamba in m1.

My data:

400 nm

433 nm

486 nm

656 nm

Of those above, which line corresponds to the transition n=3 to n=2, and from n=4 to n=2 and so on from n=6 to n=2.