The expression for the acceleration of the cart for the experiment you did in lab is a = (m1g - f) (m1 + m2) where m1 + m2 is kept constant throughout. (a) Consider the situation when friction force is zero.
What is the expression for the acceleration of the cart now? (Use the following as necessary: m1, m2, and g.) a = m1?g m1?+m2?? Correct: Your answer is correct.
If you now triple the hanging mass m1, (so m = 3m1), how will the value of the denominator for the expression for the acceleration change?
The denominator will triple in value. The denominator value will be 3m1 + m2. Tripling m1 will decrease m2 by that amount and the total mass will have a constant value as required by the experiment. Correct: Your answer is correct.
What is the expression for the acceleration now? (Use the following as necessary: m1, m2, and g.)
a = (3m1?g) (3m1?+m2?)?
Incorrect: Your answer is incorrect.
Based on your answers to the previous parts, what conclusion can you draw about the acceleration of the cart? 4 The cart's acceleration will triple as the numerator in the expression for the acceleration will triple when m1 is tripled. The cart's acceleration will remain the same as the total mass is constant during the experiment. The acceleration will increase by a certain value but not by a factor of 3. Correct: Your answer is correct. (b) Consider the situation when friction force is non-zero.
What is the expression for the acceleration of the cart now? (Use the following as necessary: m1, m2, f, and g.) a = (m1?g-ƒ) (m1?+m2?)?
Correct: Your answer is correct.
If you now triple the hanging mass m1, (so m = 3m1) how will the value of the denominator for the expression for the acceleration change? 6 The denominator will triple in value. The denominator value will be 3m1 + m2. Tripling m1 will decrease m2 by that amount and the total mass will have a constant value as required by the experiment. Correct: Your answer is correct.
What is the expression for the acceleration now? (Use the following as necessary: m1, m2, f, and g.)
a = (3m1?g-ƒ) (3m1?+m2?)?
Incorrect: Your answer is incorrect.
Based on your answers to the previous parts, what conclusion can you draw about the acceleration of the cart? 8 The cart's acceleration will triple as the numerator in the expression for the acceleration will triple when m1 is tripled. The cart's acceleration will remain the same as the total mass is constant during the experiment. The acceleration will increase by a certain value but not by a factor of 3.