The excess hcl required 43.82 ml of 0.01185m baoh2 to, Ask an Expert

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A 25ml sample of HCL was added to a 0.1g sample of CaCO3. All the CaCO3 reacted, leaving some excess HCL.

CaCO3 + 2HCL--> CaCl2+H2O+CO2

The excess HCL required 43.82 ml of 0.01185M Ba(OH)2 to complete the following reaction. What was the Molarity of the orginal HCL?

2HCL+Ba(OH)2--> BaCl2 +2H2O

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Category:- Chemistry
Reference No.:- M9464370

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