(Answered) The equilibrium constant for the following reaction

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The equilibrium constant for the following reaction is 6.59×10^-2 at 927 °C.

2 SO₃(g) <-----> 2 SO₂(g) + O₂(g) K = 6.59×10^-2 at 927 °C

Calculate the equilibrium constant for the following reactions at 927 °C

(a) 2 SO₂(g) + O₂(g) <----> 2 SO₃(g) K = ________

(b) SO₃(g) <-------> SO₂(g) + 1/2 O₂(g) K = _________

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