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The equation for the oxidation of ethanol by alcohol dehydrogenase (ADH) is CH3CH2OH + NAD+ ? CH3CH) + NADH + H+. The extinction coefficient of NADH is 6220 M-1 cm-1 + H+. If you incorrectly transcribed the extinction coefficient as 16220 M-1 cm-1, would the equilibrium constant that you calculated be higher, lower, or the same as the "true" equilibrium constant?

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