The dissociation of calcium carbonate has an equlibrium, Ask an Expert

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The dissociation of calcium carbonate has an equlibrium constant of kp=1.16 at 800 degrees c. CaCO3(s)<---->CaO9s)+CO2(g).

a. what is the kc?

b. If you place 22.5 g of CaCO3 in a 9.56 L container at 800 degrees celcius, what is the pressure of Co2 in the container.?

c. What % of the original 22.5 g sample of CaCO3 remains undercomposed at equilibrium?

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Category:- Chemistry
Reference No.:- M9868218

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