The decomposition of n2o5 in carbon tetrachloride proceeds, Ask an Expert

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the decomposition of N2O5 in carbon tetrachloride proceeds as follows: 2 N2O5 -> 4 NO2 + O2. The rate law is first order in N2O5. At 64 degree celcius the rate constant is 4.82 x 10^ 3 s ^ -1. a) Write the rate law for the reaction. b) What is the rate of reaction when [N2O5]= 0.0240 M? c) What happens to the rate when the concentration of N2O5 is doubled to 0.0480M?

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